12 volt DC wire size chart
Sized for 3 percent voltage drop, which is the limit for critical circuits under ABYC E-11 and a sensible target for anything running electronics. Length is the one-way run, since the calculation already doubles it for the return conductor.
| Amps | 5 ft | 10 ft | 15 ft | 20 ft | 25 ft | 30 ft | 40 ft |
|---|---|---|---|---|---|---|---|
| 5 | 18 | 16 | 14 | 12 | 12 | 10 | 10 |
| 10 | 16 | 12 | 10 | 10 | 8 | 8 | 6 |
| 15 | 14 | 10 | 8 | 8 | 6 | 6 | 4 |
| 20 | 12 | 10 | 8 | 6 | 6 | 4 | 4 |
| 25 | 12 | 8 | 6 | 6 | 4 | 4 | 2 |
| 30 | 10 | 8 | 6 | 4 | 4 | 2 | 2 |
| 40 | 10 | 6 | 4 | 4 | 2 | 2 | 1/0 |
| 50 | 8 | 6 | 4 | 2 | 2 | 1/0 | 2/0 |
| 100 | 6 | 2 | 1/0 | 2/0 | 3/0 | 4/0 | - |
24 volt DC wire size chart
At 24 volts the same 3 percent is 0.72 volts of allowable drop, so every cell in this table is one to two sizes smaller than the 12 volt chart. It is the practical argument for 24 or 48 volt systems on anything with long runs.
| Amps | 5 ft | 10 ft | 15 ft | 20 ft | 25 ft | 30 ft | 40 ft |
|---|---|---|---|---|---|---|---|
| 5 | 18 | 18 | 16 | 16 | 14 | 14 | 12 |
| 10 | 18 | 16 | 14 | 12 | 12 | 10 | 10 |
| 15 | 16 | 14 | 12 | 10 | 10 | 8 | 8 |
| 20 | 16 | 12 | 10 | 10 | 8 | 8 | 6 |
| 30 | 14 | 10 | 8 | 8 | 6 | 6 | 4 |
| 50 | 12 | 8 | 6 | 6 | 4 | 4 | 2 |
| 100 | 8 | 6 | 4 | 2 | 2 | 1/0 | 1/0 |
Amp capacity of wire by gauge
Voltage drop usually sets the size on DC, but the conductor still has to carry the current without overheating. These are the limits for a single conductor in free air at 30 degrees C for the small sizes DC work uses; inside a bundle or a conduit derate them.
| AWG | mm² | Amps, chassis wiring | Amps, in bundle |
|---|---|---|---|
| 22 | 0.33 | 7 | 5 |
| 20 | 0.52 | 11 | 7.5 |
| 18 | 0.82 | 16 | 10 |
| 16 | 1.31 | 22 | 13 |
| 14 | 2.08 | 32 | 17 |
| 12 | 3.31 | 41 | 23 |
| 10 | 5.26 | 55 | 33 |
| 8 | 8.37 | 73 | 46 |
| 6 | 13.3 | 101 | 60 |
The voltage drop formula
VD = 2 x K x I x L / CM, where K is 12.9 for copper, I is amps, L is one-way length in feet and CM is the conductor area in circular mils. The 2 accounts for the return conductor.
Rearranged to find the wire you need: CM = 2 x K x I x L / VD, where VD is the drop you will accept, so 0.36 volts for 3 percent of 12. Then pick the next AWG size up from the circular mil area.








