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Cylinder Force Calculator

Author: Emma Clarke, Reference Desk4 min readReviewed

Force is pressure times area. On extension the area is the full bore, so a 3 inch bore at 2,000 psi pushes 14,137 lb. On retraction the rod area is subtracted, so the same cylinder with a 1.5 inch rod pulls only 10,603 lb. That difference is why a cylinder always pushes harder than it pulls.

Hydraulics & pneumatics. Based on ISO 6020, NFPA T3.6.7.

The formula

Extension force equals pressure times the full bore area, where bore area is pi times bore diameter squared divided by four.

Retraction force equals pressure times the annulus area, which is the bore area minus the rod area. The rod occupies part of the piston face on that side, so there is less area for the fluid to act on.

In metric, force in newtons equals pressure in bar times area in square centimetres times 10. A 80mm bore at 160 bar gives 50.3 cm² times 160 times 10, which is about 80,400 N or 8.2 tonnes.

Cylinder force by bore and pressure

Extension force in pounds for common bores. Read down the bore column and across to your system pressure.

These are theoretical figures. Real output is lower by the friction of the seals and any back pressure on the return line, typically 5 to 10 percent on a well-maintained cylinder.

Extension force in lb, by bore diameter and pressure.
BoreArea (in²)1,000 psi2,000 psi3,000 psi
1.5 in1.771,7673,5345,301
2 in3.143,1426,2839,425
2.5 in4.914,9099,81714,726
3 in7.077,06914,13721,206
3.5 in9.629,62119,24228,863
4 in12.5712,56625,13337,699
5 in19.6319,63539,27058,905
6 in28.2728,27456,54984,823
8 in50.2750,265100,531150,796

How to measure a cylinder

Four numbers identify a cylinder for replacement: bore, rod diameter, stroke and the pin-to-pin retracted length.

Bore is the internal diameter of the barrel, not the outside. Measure the rod with a caliper. Stroke is the difference between fully extended and fully retracted pin-to-pin length, and measuring both is more reliable than trusting a stamped figure.

Also note the port size and thread form, the mounting type at each end, and the pin diameters. A cylinder that matches on force but not on mounting is no use.

Pneumatic cylinders

The same formula applies, but air pressures are far lower so the forces are a fraction of hydraulic. A 2 inch bore at 90 psi gives 283 lb, against 6,283 lb at 2,000 psi hydraulic.

Air is compressible, so a pneumatic cylinder will not hold position accurately against a varying load and the practical output is further reduced by pressure drop through the valve and hose. Size on at least 25 percent more force than the load needs.

Emma Clarke, Reference Desk editor at Compel GroupEmma ClarkeReference Desk

Emma looks after the reference charts and calculators. Every figure is copied from the named standard on the page rather than generated, and each page shows the date it was last checked. When a value looks wrong, the standard wins and the page gets fixed.

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Cylinder Force Calculator questions

How do I calculate hydraulic cylinder force?
Multiply system pressure by piston area. Area is pi times bore diameter squared divided by four. A 3 inch bore at 2,000 psi gives 7.07 square inches times 2,000, so 14,137 lb on extension.
Why does a cylinder pull less than it pushes?
On retraction the rod takes up part of the piston face, so the fluid acts on the bore area minus the rod area. A 3 inch bore with a 1.5 inch rod loses a quarter of its area and pulls about 10,600 lb where it pushes 14,137.
How do I measure a hydraulic cylinder for replacement?
Bore, rod diameter, stroke and retracted pin-to-pin length. Measure the barrel internal diameter rather than the outside, and take the stroke as the difference between extended and retracted pin-to-pin rather than trusting a stamp. Note port size and mounting type too.
How much force does a pneumatic cylinder give?
Far less, because shop air runs near 90 psi against 2,000 psi or more for hydraulics. A 2 inch bore gives about 283 lb on air against 6,283 lb hydraulic. Size air cylinders with at least 25 percent margin for pressure drop.
Do I need to allow for friction?
Yes. Seal friction and return-line back pressure typically cost 5 to 10 percent of theoretical force on a cylinder in good condition, and more on a worn one.

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